Mega Python

Problem:- Create a function that converts a date formatted as MM/DD/YYYY to YYYYDDMM. Examples:- format_date("11/12/2019") ➞ "20191211" format_date("12/31/2019") ➞ "20193112" format_date("01/15/2019") ➞ "20191501" Code:- Note:- Never miss indentation. If you are stuck check the python documentation. Suggestions and comments are always welcome.

Problem:- Create a function that takes a string and returns a string with its letters in alphabetical order. Examples:- alphabet_soup("hello") ➞ "ehllo" alphabet_soup("edabit") ➞ "abdeit" alphabet_soup("hacker") ➞ "acehkr" alphabet_soup("geek") ➞ "eegk" alphabet_soup("javascript") ➞ "aacijprstv" Notes:- You can assume numbers and punctuation symbols won't be included in test cases. You'll only have to deal with a single word, alphabetic characters. Code:- (You can write direct one line code like : return "".join(sorted(txt)) Note:- Never miss indentation. If you are stuck check the python documentation. Suggestions and comments are always welcome.

Problem:- Write a function that takes a credit card number and only displays the last four characters. The rest of the card numbers must be replaced by ************. Example:- card_hide("1234123456785678") ➞ "************5678" card_hide("8754456321113213") ➞ "************3213" card_hide("35123413355523") ➞ "**********5523" code:- Note:- Never miss indentation. If you are stuck check the python documentation. Suggestions and comments are always welcome.

Problem: -  Create a function that takes a single string as an argument and returns an ordered list containing the indices of all capital letters in the string. Example:- index_of_caps("eDaBiT") ➞ [1, 3, 5] index_of_caps("eQuINoX") ➞ [1, 3, 4, 6] index_of_caps("determine") ➞ [] index_of_caps("STRIKE") ➞ [0, 1, 2, 3, 4, 5] index_of_caps("sUn") ➞ [1] Notes :- Return an empty list if no uppercase letters are found in the string. Special characters ($#@%) and numbers will be included in some test cases. Assume all words do not have duplicate letters. Code:- Note:-  Never miss indentation. If you are stuck check the python documentation. Suggestions and comments are always welcome.

Problem: -  Create a function that returns the thickness (in meters) of a piece of paper after folding it n number of times. The paper starts off with a thickness of 0.5mm. Example:- num_layers(1) ➞ "0.001m" # Paper folded once is 1mm (equal to 0.001m) num_layers(4) ➞ "0.008m" # Paper folded 4 times is 8mm (equal to 0.008m) num_layers(21) ➞ "1048.576m" # Paper folded 21 times is 1048576mm (equal to 1048.576m) Code:- Note:- Never miss indentation. If you are stuck check the python documentation. Suggestions and comments are always welcome.